tag:blogger.com,1999:blog-69037163976910327922024-02-20T01:05:31.210-08:00CBSE.NIC.INAnonymoushttp://www.blogger.com/profile/16164436367878764320noreply@blogger.comBlogger10125tag:blogger.com,1999:blog-6903716397691032792.post-65896720880258878072013-06-22T05:34:00.001-07:002013-06-30T06:14:25.944-07:00Numerical Based On Square ( Mathematics )<div dir="ltr" style="text-align: left;" trbidi="on">
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>Q. Find the perimeter of a square with the following area:</b></span><br />
<div>
<div style="text-align: left;">
<ol style="text-align: left;">
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>81 m</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>36 cm</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>49 mm</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>16 dm</b></span></li>
<li><span style="background-color: white; font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>4 <span style="line-height: 16px;">µm</span></b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>9 km</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>25 inches</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>64 nm</b></span></li>
</ol>
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b>Sol.</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>1. Area of the Square = 81 m </b></span></div>
</div>
<div style="text-align: left;">
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, Area of the Square = ( side )<sup>2</sup></b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> ( side )<sup>2 </sup> = 81 m</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> side = <span style="background-color: white; line-height: 16px;">√</span> 81 m</b></span><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b> = <span style="line-height: 16px;">9</span> m</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> Perimeter of the Square = 4 x ( side ) = 4 x 9 m = 36 m</b></span><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><br /></span>
</b><br />
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>2. Area of the Square = 36 cm </b></span></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, Area of the Square = ( side )<sup>2</sup></b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> ( side )<sup>2 </sup> = 36 cm</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> side = <span style="background-color: white; line-height: 16px;">√</span> 36 cm</b></span><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">6 </span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;">cm</span></b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> Perimeter of the Square = 4 x (side) = 4 x 6 cm = 24 cm</b></span><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><br /></span>
</b><br />
<div>
<b><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">3. Area of the Square = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">49 mm</span></b><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b> </b></span></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, Area of the Square = ( side )<sup>2</sup></b></span><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> ( side )<sup>2 </sup> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">49 mm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> side = <span style="background-color: white; line-height: 16px;">√</span> </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">49 mm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">7 mm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> Perimeter of the Square = 4 x side = 4 x </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">7 mm</span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">28 mm</span></b><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b><br /></b></span>
<br />
<div>
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;">4. Area of the Square = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">16 dm</span></b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, Area of the Square = ( side )<sup>2</sup></b></span><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> ( side )<sup>2 </sup> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">16 dm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> side = <span style="background-color: white; line-height: 16px;">√</span> </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">16 dm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 dm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> Perimeter of the Square = 4 x side = 4 x </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 dm</span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">16 dm</span></b><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b><br /></b></span>
<br />
<div>
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;">5. Area of the Square = </span><span style="background-color: white; font-family: Tahoma, Arial, Helvetica, sans-serif;">4 </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif; line-height: 16px;">µm</span></b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, Area of the Square = ( side )<sup>2</sup></b></span><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> ( side )<sup>2 </sup> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 dm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> side = <span style="background-color: white; line-height: 16px;">√</span> </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 dm</span></b><br />
<b><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> = 2</span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> dm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> Perimeter of the Square = 4 x side = 4 x </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">2 dm</span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> =8</span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> dm</span></b><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b><br /></b></span>
<br />
<div>
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;">6. Area of the Square = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">9 km</span></b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, Area of the Square = ( side )<sup>2</sup></b></span><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> ( side )<sup>2 </sup> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">9 km</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> side = <span style="background-color: white; line-height: 16px;">√ </span></span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">9 km</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">3 km</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> Perimeter of the Square = 4 x side = 4 x </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">3 km</span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">12 km</span></b><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b><br /></b></span>
<br />
<div>
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;">7. Area of the Square = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">25 inches</span></b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, Area of the Square = ( side )<sup>2</sup></b></span><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> ( side )<sup>2 </sup> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">25 inches</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> side = <span style="background-color: white; line-height: 16px;">√</span> </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">25 inches</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">5 inches</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> Perimeter of the Square = 4 x side = 4 x </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">5 inches</span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">20 inches</span></b><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b><br /></b></span>
<br />
<div>
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;">8. Area of the Square = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">64 nm</span></b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, Area of the Square = ( side )<sup>2</sup></b></span><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> ( side )<sup>2 </sup> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">64 nm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> side = <span style="background-color: white; line-height: 16px;">√ </span></span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">64 nm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">8 nm</span></b><br />
<b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> Perimeter of the Square = 4 x side = 4 x </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">8 nm</span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"> = </span><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;">32 nm</span></b><br />
<b><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><br /></span></b>
<b><span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><br /></span></b>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>Q. Find the area of a square with the following perimeter:</b></span><br />
<div>
<ol>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>4 m</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>8 cm</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>12 mm</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>16 dm</b></span></li>
<li><span style="background-color: white; font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>36 <span style="line-height: 16px;">µm</span></b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>40 km</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>44 inches</b></span></li>
<li><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>48 nm</b></span></li>
</ol>
</div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>Sol. </b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>1. Perimeter of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 m</b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">Perimeter </b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side ) </b></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side )</b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> = 4 m</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> side = ( <span style="line-height: 16px;">4/4 ) </span>m</b></span><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b> = <span style="line-height: 16px;">1</span> m</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> Area of the Square = ( side )<sup>2 </sup></b><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">= ( 1 x 1 ) m = 1 m</b><br />
<b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><br /></b>
<div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>2. Perimeter of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">8 cm</b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">Perimeter </b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side ) </b></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side )</b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> = 8 cm</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> side = ( <span style="line-height: 16px;">8/4 ) c</span>m</b></span><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b> = <span style="line-height: 16px;">2</span> cm</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> Area of the Square = ( side )<sup>2 </sup></b><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">= ( 2 x 2 ) cm = 4 cm</b><br />
<br />
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>3. Perimeter of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">12 mm</b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> Also, </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">Perimeter </b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side ) </b></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side )</b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">12 mm</b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> side = ( <span style="line-height: 16px;">12/4 ) </span>mm</b></span><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b> = <span style="line-height: 16px;">3</span> mm</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> Area of the Square = ( side )<sup>2 </sup></b><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">= ( 3 x 3 ) mm = 9 mm</b><br />
<b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><br /></b>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>4. Perimeter of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">16 dm</b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>Also, </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">Perimeter </b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side ) </b></div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side )</b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">16 dm</b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> side = ( </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">16/4 </b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><span style="line-height: 16px;">) </span></b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">dm</b><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b> = <span style="line-height: 16px;">4</span> dm</b></span><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> Area of the Square = ( side )<sup>2 </sup></b><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">= ( 4 x 4 ) dm = 16 dm</b></div>
</div>
<b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><br /></b>
<div>
<div>
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>5. Perimeter of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">36 <span style="line-height: 16px;">µm</span></b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> </b></span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>Also, </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">Perimeter </b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b>of the Square = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side ) </b></div>
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<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><sup> </sup><span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">4 x ( side )</b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> = </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">36 <span style="line-height: 16px;">µm</span></b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> side = (</b></span><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><span style="line-height: 16px;"> </span></b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">36</b><span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b><span style="line-height: 16px;">/4 )</span></b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> <span style="line-height: 16px;">µm</span></b><br />
<span style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><b> = <span style="line-height: 16px;">9</span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><span style="line-height: 16px;">µm</span></b><br />
<span style="font-family: Tahoma,Arial, Helvetica, sans-serif;"><b> <span style="background-color: #f6f4f0; line-height: 16px;">∴ </span> </b></span><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"> Area of the Square = ( side )<sup>2 </sup></b><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">= ( 9 x 9 ) </b><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><span style="line-height: 16px;">µm </span></b><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;">= 81 </b><b style="font-family: Tahoma, Arial, Helvetica, sans-serif;"><span style="line-height: 16px;">µm</span></b></div>
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Pradeep Singhhttp://www.blogger.com/profile/02586909259185141193noreply@blogger.com0tag:blogger.com,1999:blog-6903716397691032792.post-3488219944373014402013-06-10T20:27:00.000-07:002013-06-17T04:34:28.410-07:00REDOX REACTIONS<div dir="ltr" style="text-align: left;" trbidi="on">
<b><span style="font-family: Arial, Helvetica, sans-serif;">REDOX REACTIONS</span></b><br />
<span style="font-family: Arial, Helvetica, sans-serif;">Reactions which involve change in oxidation number of the interacting species.</span><br />
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<b><span style="font-family: Arial, Helvetica, sans-serif;">OXIDATION</span></b><br />
<span style="font-family: Arial, Helvetica, sans-serif;">Addition of oxygen/electronegative element to a substance or removal of hydrogen /electropositive element from a substance.</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"> OR</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;">Loss of electron(s) by any species</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"> OR</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;">An increase in the oxidation no. of the element in the given substance.</span><br />
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<b><span style="font-family: Arial, Helvetica, sans-serif;">OXIDISING AGENT</span></b><br />
<span style="font-family: Arial, Helvetica, sans-serif;">Acceptor of electron(s)</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"> OR </span><br />
<span style="font-family: Arial, Helvetica, sans-serif;">A reagent which can increase the oxidation number of an element in a given substance are called as oxidants.</span><br />
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<b><span style="font-family: Arial, Helvetica, sans-serif;">REDUCTION</span></b><br />
<span style="font-family: Arial, Helvetica, sans-serif;">Removal of oxygen/electronegative element from a substance or addition of hydrogen/electropositive element to a substance.</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"> OR </span><br />
<span style="font-family: Arial, Helvetica, sans-serif;">Gain of electron(s) by any species</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"> OR</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;">An decrease in the oxidation no. of the element in the given substance.</span><br />
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<span style="font-family: Arial, Helvetica, sans-serif;"><b>REDUC</b><b>ING AGENT</b></span><br />
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<span style="font-family: Arial, Helvetica, sans-serif;">Donor of electron(s)</span></div>
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<span style="font-family: Arial, Helvetica, sans-serif;"> OR</span></div>
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<span style="font-family: Arial, Helvetica, sans-serif;">Oxidation number denotes the oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belongs entirely to more electronegative elements.</span></div>
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<b><span style="font-family: Arial, Helvetica, sans-serif;"><u>8 Rules for calculation of the oxidation number</u></span></b></div>
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<span style="font-family: Arial, Helvetica, sans-serif;">1. In elements, in the <b>free or the uncombined state</b>, each atom bears an oxidation number of <b>zero</b></span><br />
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<li><b><span style="font-family: Arial, Helvetica, sans-serif;">Ex:. <span style="background-color: white; line-height: 23px;">O</span><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2</sub> , CL<sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2</sub> <span style="background-color: white; line-height: 23px;">, </span>O<sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">3 , </sub> P<span style="background-color: white; line-height: 23px;"><b style="line-height: normal;"><sub style="border: 0px; line-height: 23px; margin: 0px; padding: 0px;">4</sub></b> , S<span style="line-height: normal;"><sub style="border: 0px; line-height: 23px; margin: 0px; padding: 0px;">8 , </sub></span></span>Na , Mg , Al</span></b></li>
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<span style="font-family: Arial, Helvetica, sans-serif;"><span style="line-height: 23px;">2. For ions composed of only one atom, the </span><span style="line-height: 23px;">oxidation </span><span style="line-height: 23px;">number</span><span style="line-height: 23px;"> is equal to the<b> </b>charge on the ion</span></span></div>
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<li><span style="font-family: Arial, Helvetica, sans-serif;"><span style="line-height: 23px;"><span style="font-size: small; line-height: normal;"><span style="font-family: Arial, Helvetica, sans-serif;"><b>Ex</b>:. oxidation number of <b>Na+</b> is <b>+1</b></span></span></span></span></li>
<li><span style="font-family: Arial, Helvetica, sans-serif;"><span style="line-height: 23px;"><span style="font-size: small; line-height: normal;"><span style="font-family: Arial, Helvetica, sans-serif;"><b>Ex</b>:. oxidation number of <b>Mg2</b><b>+</b> is <b>+2</b></span></span></span></span></li>
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<span style="font-family: Arial, Helvetica, sans-serif;">3<b>. </b> All <b>alkaline earth metals</b> have an oxidation number of <b>+2</b></span></div>
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<span style="font-family: Arial, Helvetica, sans-serif;">4<b>. </b> <b>Aluminium </b>is regarded to have an oxidation number of <b>+3 </b>in all of its compounds.</span></div>
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<span style="font-family: Arial, Helvetica, sans-serif;">5. The oxidation number of oxygen in most of the compounds is <b>-2. </b></span></div>
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<span style="font-family: Arial, Helvetica, sans-serif;"> In <b>peroxides</b> ( e.g., H</span><b><span style="font-family: Arial, Helvetica, sans-serif;"><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2</sub></span></b><span style="font-family: Arial, Helvetica, sans-serif;">O</span><b><span style="font-family: Arial, Helvetica, sans-serif;"><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2,</sub></span></b><span style="font-family: Arial, Helvetica, sans-serif;"> Na</span><b><span style="font-family: Arial, Helvetica, sans-serif;"><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2</sub></span></b><span style="font-family: Arial, Helvetica, sans-serif;">O</span><b><span style="font-family: Arial, Helvetica, sans-serif;"><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2 </sub></span></b><span style="font-family: Arial, Helvetica, sans-serif;">) each oxygen atom is assigned an oxidation number of <b>-1</b></span></div>
<span style="font-family: Arial, Helvetica, sans-serif;"><b> </b>In <b>super-oxides</b> ( e.g., KO<b><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2</sub></b>, RbO<b><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2</sub></b>) each oxygen atom is assigned an oxidation number of <b>- (1/2)</b></span></div>
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<span style="font-family: Arial, Helvetica, sans-serif;"> When oxygen atom is bonded to fluorine ( e.g., </span><span style="font-family: Arial, Helvetica, sans-serif;">OF</span><sub style="background-color: white; border: 0px; font-family: Arial, Helvetica, sans-serif; line-height: 23px; margin: 0px; padding: 0px;">2</sub><span style="font-family: Arial, Helvetica, sans-serif;"><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">, </sub></span><span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-color: white; line-height: 23px;">O</span><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2</sub></span><span style="font-family: Arial, Helvetica, sans-serif;">F</span><sub style="background-color: white; border: 0px; font-family: Arial, Helvetica, sans-serif; line-height: 23px; margin: 0px; padding: 0px;">2 </sub><span style="font-family: Arial, Helvetica, sans-serif;">) the oxygen is assigned to have a oxidation number of </span><b style="font-family: Arial, Helvetica, sans-serif;">+2 </b><span style="font-family: Arial, Helvetica, sans-serif;">and</span><b style="font-family: Arial, Helvetica, sans-serif;"> </b><b style="font-family: Arial, Helvetica, sans-serif;">+1 </b><span style="font-family: Arial, Helvetica, sans-serif;">respectively</span><b style="font-family: Arial, Helvetica, sans-serif;">.</b><br />
<span style="font-family: Arial, Helvetica, sans-serif;">6. The oxidation number of <b>hydrogen </b>is <b>+1</b>, except when it is bonded to metals in binary compounds. For example, in LiH, NaH, CaH</span><span style="font-family: Arial, Helvetica, sans-serif;"><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">2 </sub></span><span style="font-family: Arial, Helvetica, sans-serif;">its oxydation number is <b>-1</b></span><br />
<span style="font-family: Arial, Helvetica, sans-serif;">7. In all its compounds, <b>fluorine</b> has an oxidation number of <b>-1</b></span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"> Other halogens ( <b>Cl, Br and I</b>) also have an oxidation number of <b>-1 </b>as halide ions in their compounds</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;">8. The algebraic sum of the oxidation number of all the atoms in a compound must be zero.</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"> In poly-atomic ion, the algebraic sum of all the oxidation numbers of atoms of the ion must equal the charge on the ion.</span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"> Thus, the sum of oxidation number of three oxygen atoms and one carbon atom in the carbonate ion, <b>( CO</b></span><b><span style="font-family: Arial, Helvetica, sans-serif;"><sub style="background-color: white; border: 0px; line-height: 23px; margin: 0px; padding: 0px;">3 </sub></span><span style="font-family: Arial, Helvetica, sans-serif;">)</span><span style="font-family: Arial, Helvetica, sans-serif;">2</span><span style="font-family: Arial, Helvetica, sans-serif;">-</span></b><span style="font-family: Arial, Helvetica, sans-serif;"> </span><span style="font-family: Arial, Helvetica, sans-serif;"> must equal <b>-2</b>.</span><br />
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Pradeep Singhhttp://www.blogger.com/profile/02586909259185141193noreply@blogger.com0tag:blogger.com,1999:blog-6903716397691032792.post-74333521968165536622013-06-01T20:22:00.003-07:002013-06-02T19:26:27.900-07:00CH 1 Reproduction In Organisms <div dir="ltr" style="text-align: left;" trbidi="on">
<b>1. Life Span</b><b><br /></b><span style="color: #274e13;"><b><i>The period from birth to the natural death of an organism is called its life span.</i></b><b><br /></b></span><b>Examples : 1. Butter Fly ( 1-2 weeks ) 2. Tortoise ( 100-150 years )</b><b><br /></b><div>
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2. <b>Clone</b></div>
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<b><i><span style="color: #274e13;">The individual which are morphologically and genetically similar to each other and are exact copies of their parents are called clones. </span></i></b></div>
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<b>Examples : 1. Amoeba ( Produced by binary fission ), 2. Yeast ( Produced by budding )</b></div>
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<b>3. Reproduction</b></div>
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<b><i><span style="color: #274e13;">The biological process in which in which an organism gives rise to young ones ( offspring ) similar to itself, is called reproduction.</span></i></b></div>
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<span style="background-color: #f6f4f0;"><span style="font-family: verdana, helvetica, arial, sans-serif;"><span style="font-size: 12px; line-height: 16px;">→ it enables the continuity of the species, generation after generation.</span></span></span></div>
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<span style="background-color: #f6f4f0; font-family: verdana, helvetica, arial, sans-serif; font-size: 12px; line-height: 16px;">→ factors affecting reproduction</span></div>
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<span style="background-color: #f6f4f0;"><span style="font-family: verdana, helvetica, arial, sans-serif;"><span style="font-size: 12px; line-height: 16px;"> 1. Organism Habitat</span></span></span></div>
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<span style="background-color: #f6f4f0;"><span style="font-family: verdana, helvetica, arial, sans-serif;"><span style="font-size: 12px; line-height: 16px;"> 2. Internal Physiology </span></span></span></div>
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Pradeep Singhhttp://www.blogger.com/profile/02586909259185141193noreply@blogger.com0tag:blogger.com,1999:blog-6903716397691032792.post-91033918644938061492013-05-31T07:41:00.001-07:002013-05-31T07:41:51.928-07:00All toppers of cbse class 12th 2013<div dir="ltr" style="text-align: left;" trbidi="on">
<h2 style="text-align: left;">
<span style="font-family: Arial, Helvetica, sans-serif;">All India Toppers 2013</span></h2>
<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>Paras Sharma </b> </span><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>99%</b></span></span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>School - </b>Lancer Convent Senior Secondary School ( </span><span style="background-color: white; font-size: 15px; line-height: 23px;">Outer Delhi </span><span style="background-color: white; font-size: 15px; line-height: 23px;">)</span></span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>Stream - </b></span><span style="background-color: white; font-size: 15px; line-height: 23px;">Commerce stream</span></span><br />
<span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;"><span style="color: blue;">mathematics</span> - <span style="background-color: white;"><b>100</b></span>, <span style="color: blue;">accountancy</span></span><span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;">- <b>100</b></span><span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;">, <span style="color: blue;">economics </span></span><span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;">- <b>100</b></span><span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;"><b> </b>and <span style="color: blue;">business studies</span> </span><span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;">- <b>100</b></span><span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;"><b> </b>and <span style="color: blue;">English</span></span><span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;"><span style="color: blue;"> </span></span><span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;"><b>95</b></span><span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;">.</span><br />
<span style="font-family: arial; font-size: 12px; line-height: 16px; text-align: justify;">He scored 495 out of 500.</span><br />
<span style="background-color: white; font-size: 15px; line-height: 23px;"><span style="font-family: Arial, Helvetica, sans-serif;"><br /></span></span>
<span style="background-color: white; font-size: 15px; line-height: 23px;"><b><span style="font-family: Arial, Helvetica, sans-serif;">Sopan Khosla 99%</span></b></span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"><b style="font-size: 15px; line-height: 23px;">School </b><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>- </b></span><span style="background-color: white; font-size: 15px; line-height: 23px;">DPS ( </span><span style="background-color: white; font-size: 15px; line-height: 23px;">Jabalpur, Madhya Pradesh </span><span style="background-color: white; font-size: 15px; line-height: 23px;">)</span><span style="background-color: white; font-size: 15px; line-height: 23px;"> </span></span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"><b style="font-size: 15px; line-height: 23px;">Stream </b><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>- </b></span><span style="background-color: white; font-size: 15px; line-height: 23px;">Science stream</span></span><br />
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<h2>
<span style="font-family: Arial, Helvetica, sans-serif;">All Delhi Govt. School Toppers 2013</span></h2>
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<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>Ankit Saini </b></span><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>97.4%</b></span></span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"><b style="font-size: 15px; line-height: 23px;">School </b><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>- </b></span><span style="background-color: white; font-size: 15px; line-height: 23px;">Rajkiya Pratibha Vikas Vidyalaya </span></span><br />
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<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>Stream - </b></span><span style="background-color: white; font-size: 15px; line-height: 23px;">Commerce stream</span></span><br />
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<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-color: white; font-size: 15px; line-height: 23px;"><br /></span></span></div>
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<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>Lalit Lakra </b></span><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>96.2%</b></span></span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"><b style="font-size: 15px; line-height: 23px;">School </b><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>-</b> </span><span style="background-color: white; font-size: 15px; line-height: 23px;">SV school ( </span><span style="background-color: white; font-size: 15px; line-height: 23px;">Paschim Vihar, Delhi</span><span style="background-color: white; font-size: 15px; line-height: 23px;">) </span></span><br />
<span style="font-family: Arial, Helvetica, sans-serif;"><b style="font-size: 15px; line-height: 23px;">Stream - </b><span style="background-color: white; font-size: 15px; line-height: 23px;">Science stream</span></span><br />
<span style="background-color: white; font-size: 15px; line-height: 23px;"><span style="font-family: Arial, Helvetica, sans-serif;"><br /></span></span>
<span style="font-family: Arial, Helvetica, sans-serif;"><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>Momina Sheikh </b></span><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>95.2%</b></span></span><br />
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<span style="font-family: Arial, Helvetica, sans-serif;"><b style="font-size: 15px; line-height: 23px;">School </b><span style="background-color: white; font-size: 15px; line-height: 23px;"><b>-</b> </span></span><span style="background-color: white; font-family: Georgia, 'Times New Roman', Times, serif; font-size: 15px; line-height: 23px;">Shakti Nagar</span><br />
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<b style="font-family: Arial, Helvetica, sans-serif; font-size: 15px; line-height: 23px;">Stream - </b><span style="background-color: white; font-family: Georgia, 'Times New Roman', Times, serif; font-size: 15px; line-height: 23px;">Arts </span><span style="background-color: white; font-family: Arial, Helvetica, sans-serif; font-size: 15px; line-height: 23px;">stream</span></div>
<div>
<span style="background-color: white; font-family: Georgia, 'Times New Roman', Times, serif; font-size: 15px; line-height: 23px;"><br /></span></div>
<div>
<span style="background-color: white; font-family: Georgia, 'Times New Roman', Times, serif; font-size: 15px; line-height: 23px;"><b>Diksha </b></span><span style="background-color: white; font-family: Georgia, 'Times New Roman', Times, serif; font-size: 15px; line-height: 23px;"><b>95.2%</b></span></div>
<div>
<b style="font-family: Arial, Helvetica, sans-serif; font-size: 15px; line-height: 23px;">School </b><span style="background-color: white; font-family: Arial, Helvetica, sans-serif; font-size: 15px; line-height: 23px;"><b>- </b></span><span style="background-color: white; font-family: Georgia, 'Times New Roman', Times, serif; font-size: 15px; line-height: 23px;">Nangloi</span></div>
<div>
<b style="font-family: Arial, Helvetica, sans-serif; font-size: 15px; line-height: 23px;">Stream - </b><span style="background-color: white; font-family: Georgia, 'Times New Roman', Times, serif; font-size: 15px; line-height: 23px;">Arts </span><span style="background-color: white; font-family: Arial, Helvetica, sans-serif; font-size: 15px; line-height: 23px;">stream</span></div>
<div>
<span style="background-color: white; font-family: Arial, Helvetica, sans-serif; font-size: 15px; line-height: 23px;"><br /></span></div>
<div>
<span style="background-color: white; font-family: Georgia, 'Times New Roman', Times, serif; font-size: 15px; line-height: 23px;"><b>Taruna 92.8%</b></span></div>
<br />
<b style="font-family: Arial, Helvetica, sans-serif; font-size: 15px; line-height: 23px;">Stream - </b><span style="background-color: white; font-family: Georgia, 'Times New Roman', Times, serif; font-size: 15px; line-height: 23px;">vocational stream</span><br />
<br /></div>
Anonymoushttp://www.blogger.com/profile/16164436367878764320noreply@blogger.com0tag:blogger.com,1999:blog-6903716397691032792.post-22481316498804325042013-05-31T05:18:00.000-07:002013-05-31T05:18:10.172-07:00CBSE Class 12th Result 2013<div dir="ltr" style="text-align: left;" trbidi="on">
<br />
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="font-family: inherit;"><strong>CBSE board class 12th results 2013</strong> has been declared by the Central Board of Secondary Education (CBSE) on 27th May, Monday as announced earlier.</span></div>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="background-color: white; line-height: 20px;">In the CBSE Class 12th Result 2013 declared on Monday, Chennai once again put up the best performance with a pass percentage of 91.83.</span><br style="background-color: white; line-height: 20px; outline-style: none;" /><br style="background-color: white; line-height: 20px; outline-style: none;" /><span style="background-color: white; line-height: 20px;">The results this year in particular assumes significance for students who aspire to make it to the IITs as weightage is given for the Class XII performance.</span><br style="background-color: white; line-height: 20px; outline-style: none;" /><br style="background-color: white; line-height: 20px; outline-style: none;" /><span style="background-color: white; line-height: 20px;">Accordingly, the cut off score for the top 20 percentile will be 391 for general category students this year, a statement issued by the CBSE said. For OBC, it will be 389, SC 350 and ST 338.</span><br style="background-color: white; line-height: 20px; outline-style: none;" /><br style="background-color: white; line-height: 20px; outline-style: none;" /><span style="background-color: white; line-height: 20px;">Rank holders in the JEE advance under the new format must be among the top 20 performers for admission to the IITs.</span><br style="background-color: white; line-height: 20px; outline-style: none;" /><br style="background-color: white; line-height: 20px; outline-style: none;" /><span style="background-color: white; line-height: 20px;">Over 82 per cent students cleared the 2013 Class XII CBSE examinations, with girls once again outshining the boys and the Chennai region beating others in the overall pass percentage.</span><br style="background-color: white; line-height: 20px; outline-style: none;" /><br style="background-color: white; line-height: 20px; outline-style: none;" /><span style="background-color: white; line-height: 20px;">The results were declared across the country today, with the total pass percentage standing at 82.10 per cent, an increase of about two per cent over the last year, said a statement. </span><br style="background-color: white; line-height: 20px; outline-style: none;" /><br style="background-color: white; line-height: 20px; outline-style: none;" /><span style="background-color: white; line-height: 20px;">In all, 9,44,721 students registered for the Class XII examination this year, which was also an increase of 15.81 per cent over 2012.</span><br style="background-color: white; line-height: 20px; outline-style: none;" /><br style="background-color: white; line-height: 20px; outline-style: none;" /><span style="background-color: white; line-height: 20px;">Girls continued to fare better than boys with 87.98 per cent clearing the exam as compared to 77.78 per cent boys.</span></div>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="font-family: inherit;">The <strong>results of CBSE 12th 2013</strong> are now available on the official website of CBSE board at<a href="http://cbseresults.nic.in/" style="color: black; text-decoration: none;"><strong>http://cbseresults.nic.in/</strong></a>.</span></div>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="font-family: inherit;">In addition to that, the candidates can also check their <strong>CBSE board class 12th results 2013</strong>through SMS as CBSE has provided different numbers for all service holders, those are:</span></div>
<ul>
<li><span style="color: blue; font-family: inherit;">For MTS users: Type: cbse12 rollno, Send SMS to 543216</span></li>
<li><span style="color: blue; font-family: inherit;">For BSNL Users: cbse12 rollno, Send SMS to 57766</span></li>
<li><span style="color: blue; font-family: inherit;">For Tata Teleservice (Indicom, Docomo): Type cbse12 rollno, Send SMS to 54321, 51234,5333300</span></li>
<li><span style="color: blue; font-family: inherit;">For Aircel users: Type cbse12 rollno, Send SMS to 5800001</span></li>
<li><span style="color: blue; font-family: inherit;">For Airtel users: Type cbse12 rollno, Send SMS to 5207011</span></li>
<li><span style="color: blue; font-family: inherit;">For NIC users: Type cbse12 rollno, Send SMS to 9212357123</span></li>
<li><span style="color: blue; font-family: inherit;">For Vodafone users: Type cbse12 rollno, Send SMS to 50000</span></li>
<li><span style="color: blue; font-family: inherit;">For Jagran users: Type cbse12 rollno, Send SMS to 57272</span></li>
</ul>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="font-family: inherit;">The Central Board of Secondary Education had conducted the CBSE class 12th examination from March1, 2013 to April 17, 2013 in which lakhs of students appeared and were waiting for their <strong>CBSE 12th results 2013</strong> anxiously for their results since then.</span></div>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="font-family: inherit;">The CBSE board class 12th results 2013 are considered even more important as it opens the gates for the students to take admission for further education as many states including Bihar, Meghalaya, Assam, Kerala, Karnataka, Tamil Nadu and Rajasthan have already declared their results of class 12th board.</span></div>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="font-family: inherit;">Moreover, the results of AIEE JEE (Main) exam has already been declared by CBSE and the declaration of CBSE class 12th results would enable the students admission to IIT, NIT and other engineering institutes which would begin after the declaration of class 12th results by CBSE.</span></div>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="font-family: inherit;">Many schools including Kendriya Vidyalayas, Jawahar Navodaya Vidyalayas, private schools, Government Schools, Independent Schools and Central Tibetean Schools are affiliated from CBSE at present and is considered to be one of the biggest exam of the country.</span></div>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="font-family: inherit;">To Check CBSE Class 12th results 2013: <strong><a href="http://cbseresults.nic.in/class12/cbse122013.htm" style="color: black; text-decoration: none;">Click here</a></strong></span></div>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
<span style="font-family: inherit;"><br /></span></div>
<div style="margin-left: 10px; margin-right: 10px; padding: 5px;">
</div>
<div style="background-color: white; border: 0px none; color: #333333; line-height: 20px; margin: 0px; outline: none; padding: 0px; text-align: justify;">
<span style="font-family: inherit;"><b style="border: 0px; margin: 0px; outline: none; padding: 0px;">Delhi: </b>CBSE Chairman Vineet Joshi has said that students now get a chance to verify their marks. The candidate can either apply online or download the offline form. However, the request can be made only after 31 days of declaration of the result on the internet.</span></div>
<div style="background-color: white; border: 0px none; color: #333333; line-height: 20px; margin: 0px; outline: none; padding: 0px; text-align: justify;">
<span style="font-family: inherit;"> </span></div>
<div style="background-color: white; border: 0px none; color: #333333; line-height: 20px; margin: 0px; outline: none; padding: 0px; text-align: justify;">
<span style="font-family: inherit;">Candidates applying online should send the printout of page generated on submission of form along with a demand draft of requisite fee to the regional office concerned. Candidates of Delhi region can also deposit fee at designated Schools of Delhi Region.</span></div>
<div style="background-color: white; border: 0px none; color: #333333; line-height: 20px; margin: 0px; outline: none; padding: 0px; text-align: justify;">
<span style="font-family: inherit;"> </span></div>
<div style="background-color: white; border: 0px none; color: #333333; line-height: 20px; margin: 0px; outline: none; padding: 0px; text-align: justify;">
<b style="border: 0px; margin: 0px; outline: none; padding: 0px;"><span style="font-family: inherit;">Compartment examinations from 6th July </span></b></div>
<div style="background-color: white; border: 0px none; color: #333333; line-height: 20px; margin: 0px; outline: none; padding: 0px; text-align: justify;">
<span style="font-family: inherit;"> </span></div>
<div style="background-color: white; border: 0px none; color: #333333; line-height: 20px; margin: 0px; outline: none; padding: 0px; text-align: justify;">
<span style="font-family: inherit;">The compartment examinations of High School will be held on July 16. Students can obtain forms from the DIOS office. The first chance compartmental examination will be held on 16th July 2013. Regular candidates are required to route their requests through their respective schools. The institutions must ensure that the list of compartmental candidate reaches the respective regional offices with fee upto 21.06.2013 or with late fee of Rs 10/- per day upto 29.06.2013.</span></div>
<div style="background-color: white; border: 0px none; color: #333333; line-height: 20px; margin: 0px; outline: none; padding: 0px; text-align: justify;">
<span style="font-family: inherit;"><br /></span></div>
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Anonymoushttp://www.blogger.com/profile/16164436367878764320noreply@blogger.com0tag:blogger.com,1999:blog-6903716397691032792.post-59388860090002564172012-12-07T17:49:00.001-08:002012-12-07T17:49:58.394-08:00CBSE 12th TOPPER 2012 <div dir="ltr" style="text-align: left;" trbidi="on">
<h2 style="text-align: left;">
CBSE Class XII Science Topper's Views</h2>
<h2 style="text-align: left;">
Mohammad Ismat</h2>
<br />
Mohammad Ismat is All India topper for CBSE Class XII exam 2012
<br />
<div align="center">
<img alt="Mohammad Ismat is All India topper for CBSE Class XII exam 2012" border="0" class="frame" height="250" src="http://e-paolive.net/galleries/images/Science_Education/Student/2012/Mohammad_Ismat_05/Mohammad_Ismat_201205_2.jpg" width="250" /> <br />
<i>Mohammad Ismat - All India topper for CBSE Class XII exam 2012 :: Pix - David M Mayum</i>
</div>
<div align="justify">
<br />
<br />
Mohammad Ismat from Manipur was declared the All India topper in the CBSE Class XII exam on May 28 2012.
<br />
<br />
He attended Zenith Academy Sangaiprou, Airport Road,Imphal
<br />
<br />
Mohammad Ismat , a resident of Lilong Haoreibi Mayai Leikai , is the son of Bashirur Rahmam and (L) Shahidan Bibi
<br />
</div>
<div align="center">
<img alt="Mohammad Ismat All India topper for CBSE Class XII exam 2012 MArk Sheet" border="0" class="frame" src="http://www.e-paolive.net/galleries/images/misc/2012/05/MOHAMMAD-ISMAT-CBSE-2012-Topper.gif" /> </div>
<div align="justify">
<br />
<br />
The marks obtained in the CBSE Class XII exam are<br />
English - 98<br />
Math - 100<br />
Chemistry - 100<br />
Physics - 97<br />
Home - 100<br />
Fine Art - 100
<br />
<br />
From <a href="http://e-pao.net/ge.asp?heading=1&mx=&src=290512" target="EP">Hueiyen Lanpao - Link here</a>
<br />
</div>
<blockquote class="style1">
<i>In an exclusive interview to Hueiyen Lanpao at Zenith Academy today,
Md Ismat expressed extreme happiness over his success and showed
gratitude to almighty Allah for His blessing in securing the coveted top
position in the All India Senior Secondary Certificate Examination
(AISSCE), 2012 . The topper gave all credits for his grand success to
his parents, teachers and well wishers and also thanked S Manaoton,
Secretary of the school for his immense support towards achieving his
goal.
<br /><br />
Md Ismat informed that normally he studied for around 6 hours a day but
increased the duration of study to 8-10 hours when the examination
approached. Md Ismat said that he plans to graduate in Physics and
become an IAS officer in future. However, he also has the desire to
become a scientist one day, he hastened add, saying he enjoys reading
various science books/magazines.
<br /><br />
In his message to the students of Manipur, Md Ismat said that one ought
to control his/her desire, direct their action to a specific aim, live
simple and think high rather than paying more attention to fashion and
luxury items. He also suggested that full focus should be given to their
studies.
<br /><br />
Father of Md Ismat MV Basirur Rahman, who is a teacher at Lilong
Chagaipokpi Lower Primary Madrassa, said he is overwhelmed by his son's
achievement. "Ismat's weak health and financial problem in the family
acted as obstacles in his study. However, he has defied all odds and
came out successful", the proud father added. </i>
</blockquote>
<br />
<br />
From <a href="http://e-pao.net/ge.asp?heading=14&mx=&src=290512" target="EP">The Sangai Express - Link here</a>
<br />
<br />
<blockquote class="style1">
<i>"Impossible is not in my mind and I have the strong conviction that
everything is possible when a man is determined. And it is this belief
which helped me in my examination," a jubilant Ismat told this reporter
minutes after the results were declared.
<br /><br />
"After passing my Class X examination I thought of studying in some
schools in Imphal considered to be among the best ones in Manipur but I
could not because of the acute financial difficulties faced by my
families," he recalled.
<br /><br />
"All was not lost as Sir SM Singh the management secretary of Zenith
Academy, Imphal accepted my request to study in the school at the barest
fees and with his kind guidance and advice I have come out with flying
colors," he said. " I'm planning to study at St Stephens , New Delhi and
work hard to top the civil services exams," Ismat , who treats books as
his best friends, said.
<br /><br />
"My happiness knew no bounds. My son Ismat has done it and I think he
would definitely become a leader to guide thousands of poor students to
become great personalities," an emotional Bashirur Rahman said.
</i>
</blockquote>
<br />
<br />
From <a href="http://timesofindia.indiatimes.com/home/education/news/Manipuri-boy-tops-CBSE-class-XII-exams/articleshow/13609040.cms" target="EP">Times of India - Link here</a>
<br />
<br />
<blockquote class="style1">
<i>"After passing class X with high marks I thought of studying in the
best school in Imphal. But I could not due to the acute financial
difficulties faced by my family. All is not lost when S M Singh, the
management secretary of Zenith Academy accepted my request to study in
the school without charging much fees. With his guidance, I have come
out with flying colours," Ismat said.
<br /><br />
"Impossible is not in my mind and I have the strong conviction that
everything is possible when a man determined to do what mankind can do.
And this is the only tool for me to top in this national level
examination," a jubilant Ismat told TOI minutes after the results were
declared.</i>
</blockquote>
<br />
<br />
From <a href="http://www.hindustantimes.com/India-news/Imphal/Manipur-boy-all-India-topper-with-99-6-in-science-stream/Article1-862733.aspx" target="EP">Hindustan Times - Link here</a>
<br />
<br />
<blockquote class="style1">
<i>"Never leave till tomorrow what you can do today. This was the
success mantra of Mohammad Ismat, who topped the All India CBSE Class 12
exam, the results of which were declared on Monday.
<br /><br />
He wants to pursue Physics (Honours) from St Stephen’s College in Delhi, and crack the Civil Service exam later.
<br /><br />
Referring to last year’s four-month long blockade of the national
highways to Manipur, the economic lifeline of the state, Ismat said,
“The turmoil in the state was a stumbling block but it worked as a
challenge of sorts.”</i>
</blockquote>
<br />
<br />
<div align="center">
<img alt="Mohammad Ismat is All India topper for CBSE Class XII exam 2012" border="0" class="frame" height="250" src="http://e-paolive.net/galleries/images/Science_Education/Student/2012/Mohammad_Ismat_05/Mohammad_Ismat_201205_4.jpg" width="250" /> <br />
<i>Mohammad Ismat - All India topper for CBSE Class XII exam 2012 :: Pix - David M Mayum</i>
</div>
</div>
Anonymoushttp://www.blogger.com/profile/16164436367878764320noreply@blogger.com1tag:blogger.com,1999:blog-6903716397691032792.post-19569268143339111862012-12-07T17:46:00.000-08:002012-12-07T17:48:27.296-08:00CLASS 10TH TOPPERS 2012<div dir="ltr" style="text-align: left;" trbidi="on">
Post the launch of Continuous and Comprehensive Evaluation (<span class="caps" style="color: lime;">CCE</span>) system, Central Board of Secondary Education (<span class="caps">CBSE</span>)
class 10th results that were declared on Thursday saw many toppers.
There are hundreds of students who have scored a perfect 10 in
Cumulative Grade Point Average.<br />
“I am pretty sure I will get an A1 in all the subjects, so there is
no anxiety as such. Also there is no tension whether I score 95 or 96
per cent,” says Varnika Chawla of Delhi Public School, R K Puram.<br />
Any student who has secured between 91 and 100 in a subject, has an
<span style="color: cyan;">A1</span> and a grade point of 10. Thereby any student who has scored more than
91 in every subject has a grade point of 10 and hence qualifies to be
labelled among <span class="caps">CBSE</span> Class 10th toppers.<br />
Scores between 81-90 fetch an<span style="color: #ffd966;"> </span><span style="color: yellow;"><span style="color: #a2c4c9;">A2</span> </span>grade or 9 points; 71-80, <span style="color: #674ea7;">B1</span> or 8
points; 61-70, <span style="color: lime;">B2</span> or 7 points; 51-60, <span style="color: #c27ba0;">C1</span> or 6 points; 41-50, <span style="color: #3d85c6;">C2 </span>or 5
points and 33-40, <span style="color: #a64d79;">D </span>or 4 points. <span style="color: #274e13;">D </span>is the qualifying grade, and those
scoring between 21-32 <span style="color: red;">E1</span> and 20 and below-<span style="color: red;">E2</span> will be required to improve
their performance.<br />
<span class="caps">SBOA</span> school has 142 ten-pointers out of 687 students who appeared for Class X exams and <span class="caps">DAV</span>
Gopalapuram, produced over 100 ten-pointers. Not just these, there are
many schools across the nation that have a huge number of ten pointers
and it is hard to figure out the actual <span class="caps">CBSE</span> Class 10th toppers this time.<br />
You may also like to know about<span style="color: magenta;"> CBSE 12th Topper 2012</span>.<br />
<span style="color: magenta;"><u><i><b>Avanya Singh </b></i></u></span></div>
Anonymoushttp://www.blogger.com/profile/16164436367878764320noreply@blogger.com0tag:blogger.com,1999:blog-6903716397691032792.post-13595035506330796852012-12-07T17:44:00.000-08:002012-12-07T17:44:04.881-08:00CBSE Attendance Rules and Regulations 2012-13<div dir="ltr" style="text-align: left;" trbidi="on">
<h2 style="text-align: left;">
<u style="background-color: white; color: black;">Here is the latest rules and regulations issued by CBSE</u></h2>
<div style="text-align: left;">
The expression “a regular course of study” referred to in the Exam Bye-Laws means at least <b>75%</b>
of attendance in the classes held: counted from the day of commencement
of teaching of classes X upto the 1st of the month preceding the month
in which the examination of the Board commences.</div>
Candidates taking
up subject(s) involving practicals shall also be required to have put
in at least 75% of the total attendance for practical work in the
subject in the laboratory. Head of Institutions shall not allow a
candidate who has offered subject(s) involving practicals to take the
practical examination(s) unless the candidate fulfils the attendance
requirements as given in this Rule.<br />
<b>(ii)</b> The
candidates who had failed in the same examination in the preceding year
and who rejoins class X shall be required to put in 75% of attendance
calculated on the possible attendance from the Ist of the month
following the publication of the results of that examination by the
Board upto the Ist of the month preceding the month in which the
examination of the Board commences.<br />
<b>(iii)</b> In the
case of migration from other institution, attendance at the institution
school recognised by the Education Department of the State/Union
Territory from which the candidate migrates will be taken into account
in calculating the required percentage of attendance.<br />
<h3>
<u>Requirement of Attendance in Subjects of Internal Assessment</u></h3>
<b>(i)</b>
No student from a School affiliated to the Board shall be eligible to
take the examination unless he has completed 75% of attendance counted
from the opening of Class X upto the Ist of the month preceding the
month in which the examination commenes in the subjects of internal
assessment.<br />
<b>(ii)</b> Exemption from W.E./Art
Education/P & HE may be granted to a candidate on medical grounds
provided the application is supported by a certificate given by a
Registered Medical Officer of the rank not below that of Asstt. Surgeon
and forwarded by the Head of the School with his recommendations.<br />
<b>(iii)</b> The Chairman shall have powers to condone shortage of attendances in subjects of internal assessment.<br />
<h3>
<u>RULES FOR CONDONATION OF SHORTAGE OF ATTENDANCES</u></h3>
<b>(i)</b>
If a candidate’s attendance falls short of the prescribed percentage,
the Head of the School may submit his name to the Board provisionally.
If the candidate is still short of the required perecentage of
attendance within three needs of the commencement of the examination,
the Head of the institution shall report the case to the regional
Officer concerned immediately. If in the opinion of the Head of the
institution, the candidate deserves special consideration, he may submit
his recommendation to the Regional Officer concerned not later than
three weeks before the commencement of the examination for condonation
of shortage in attendances by the Chairman, CBSE, who may issue orders
as he may deem proper. The Head of the School, in his letter requesting
for condonation of shortage in attendance should given the maximum
possible attendance by a student counted from the day of commencement of
teaching of classes X (beginning of the session) upto the Ist of the
month preceding the month in which the examination of the Board
commences, attendance by the Candidate in question during the aforesaid
period & the percentage of attendance by such candidate during the
aforesaid period.<br />
<b>(ii)</b> Shortage upto 15% only may
be condoned by the Chairman. Cases of candidates with attendance below
60% in Class-X shall not be considered and Class-XII, as the case may
be, shall be considered for condonation of shortage of attendance by the
Chairman only in exceptional circumstances created on mediacal grounds,
such as candidate suffering from serious diseases like Cancer, AIDS,
T.B. or any other disease or injury requiring long period of
hospitalization.<br />
<b>(iii)</b> The Principal shall refer a
case of shortage within the above prescribed limit of condonation to
the Board, either with the recommendations or with valid reasons for not
recommending the case.<br />
<b>(iv)</b> The following may be
considered valid reasons for recommending the case of the candidates
with attendance less than the prescribed percentage :-<br />
<ul>
<li>Prolonged illness.</li>
<li>loss of father/mother or some other such incident leading to his absence from the school and meriting special consideration.</li>
<li>any other reason of similar serious nature.</li>
</ul>
<b>(v)</b> Authorized participation in sponsored tournaments and Sports’ meet of
not less than inter school level and at NCC/NSS Camps including the days
of journeys for such participation shall be counted as full attendance.<br />
<span style="color: magenta;"><u><i><b>Avanya Singh</b></i></u></span></div>
Anonymoushttp://www.blogger.com/profile/16164436367878764320noreply@blogger.com0tag:blogger.com,1999:blog-6903716397691032792.post-52662114468756467182012-12-07T17:41:00.000-08:002012-12-07T17:41:12.391-08:00CBSE Improvement FAQ's 2012-2013<div dir="ltr" style="text-align: left;" trbidi="on">
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<b>#1.</b> Is improvement exam mark sheet is valid in all states? <br />
<b><span style="color: blue;">Ans</span><span style="color: red;">.</span></b>
Yes, The mark-sheet will be valid in all states of India but keep one
thing in mind you have to choose the all India type i.e. AISSCE. <br />
<b>#2.</b> How many times can a candidate appear for Improvement examination?<br />
<b><span style="color: blue;">Ans</span><span style="color: #cc0000;">.</span></b> For improvement examination only one chance in the succeeding year is permitted.<br />
<b>#3. </b> Is a student required to appear in all subjects in improvement examination?<br />
<b><span style="color: blue;">Ans<span style="color: red;">.</span></span> </b>No, the student can appear in one or more than one subject(s) as
per his/her choice. However, improvement exam. can be taken only in the
successive year of passing Class XII exams.<br />
<b>#4.</b> Can a candidate simultaneously appear for Improvement as well as Additional subject examination?<br />
<b><span style="color: blue;">Ans</span><span style="color: #cc0000;">. </span></b> No, a candidate appearing for Improvement in one or more subjects
cannot appear for additional subject examination simultaneously.<br />
<b>#5.</b> I wish to improve my performance in Chemistry and Maths in class XII. Is it possible and how?<br />
<b><span style="color: blue;">Ans</span><span style="color: #cc0000;">.</span></b> A candidate who has passed Class XII examination of the Board may
reappear for improvement of performance in one or more subjects in the
main examination in the succeeding year only. The candidate may appear
privately; those re-appearing for whole examination can also appear as
regular candidate if admitted by the school.<br />
<b>#6.</b> What is the eligibility criteria for a student to appear as a private candidate in Board<br />
<div dir="ltr" style="text-align: left;">
examination?<br />
<b><span style="color: blue;">Ans</span><span style="color: red;">.</span></b> The Board prescribes following conditions under which a candidate can appear privately: -<br />
<ol>
<li>Failed candidates</li>
<li>Teachers serving in educational institutions</li>
<li>Women candidates who are bonafide residents of NCT of Delhi and</li>
<li>Physically handicapped students</li>
</ol>
</div>
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<b>#7.</b> Is it possible for a student who has failed in Science stream in Class XII to change subjects<br />
to pass at subsequent examination?</div>
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<b><span style="color: blue;">Ans</span><span style="color: red;">.</span></b> Yes, but with prior permission of the Board.</div>
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<b>#8.</b> I appeared in the compartment examination in July-August, but failed again, do I now have<br />
to re-appear in all subjects again?<br />
<b><span style="color: blue;">Ans</span><span style="color: red;">.</span></b> The Board gives three chances to clear the compartment examination. The first<br />
examination is held in July-August followed by second chance in March-April and the third<br />
chance in July-August. Unsuccessful candidates after these three attempts are required to appear<br />
afresh in all subjects there on.<br />
<b>#9. </b> I wish to improve my performance in Chemistry and Maths. Is it possible and how?<br />
<b><span style="color: blue;">Ans</span><span style="color: red;">.</span></b> A candidate who has passed Class X or XII examination of the Board may re-appear for<br />
improvement of performance in one or more subjects in the main examination in the succeeding<br />
year only. The candidate may appear privately; those re-appearing for whole examination can<br />
also appear as regular candidate if admitted by the school.<br />
<ul>
<li>For
subjects involving practical work, if the candidate has passed the
practical examination, he or she will be allowed to appear only in
theory part.</li>
<li>Only a statement of marks is issued by the Board after the improvement of performance. </li>
</ul>
<b>#10.</b> Is it compulsory to pass in theory and practical exams. Separately?<br />
<b><span style="color: blue;">Ans</span><span style="color: red;">.</span> </b> Yes, it is compulsory to pass separately in the subjects involving theory and practical in<br />
Class XII.<br />
<b>#11.</b> Is a student required to appear in all subjects in improvement examination?<br />
<b><span style="color: blue;">Ans</span><span style="color: red;">.</span> </b> No, the student can appear in one or more than one subject(s) as per his/her choice.<br />
However, improvement exam. can be taken only in the successive year of passing Class X/XII<br />
exams.<br />
<b>#12.</b> Is the candidate allowed to see the answer script in case the result is not as per the<br />
expectations?<br />
<b><span style="color: blue;">Ans</span><span style="color: red;">.</span></b> No. There is no provision of showing answer scripts. The candidate can apply for<br />
scrutiny, for reconfirmation of marks.<br />
<b>#13.</b> If a candidate passes in the additional subject but fails in one of the main subjects, what will<br />
the result show?<br />
<b><span style="color: blue;">Ans</span><span style="color: red;">.</span></b><span style="color: red;"> </span> The candidate will be considered as having passed the examination in such a case. A<br />
language will replace a language only. For further details the scheme of examinations can be<br />
referred to.<br />
<b>#14.</b> What is the procedure followed in marking the answers?<br />
<b><span style="color: blue;">Ans<span style="color: red;">.</span></span></b> Each answer is divided into steps and marks are given in accordance to the weightage<br />
assigned for these steps. It is advised that a copy of Marking Scheme be procured to get a clear<br />
idea.<br />
<b>#15. </b> The result of Patrachar candidates is always very poor, is the evaluation of<br />
private/patrachar candidates different from that of regular candidates?<br />
<span style="color: blue;"><b>Ans<span style="color: red;">.</span></b> </span>
There is no difference in the evaluation procedures. However, it
depends entirely on the level of preparation and performance of
individual candidates irrespective of their status.<br />
<b>#16.</b> Can a candidate simultaneously appear for Improvement as well as Additional subject<br />
examination?<br />
<b><span style="color: blue;">Ans<span style="color: #cc0000;">.</span></span> </b> No, a candidate appearing for Improvement in one or more subjects cannot appear for<br />
additional subject examination simultaneously.<br />
<b>#17. </b> How many times can a candidate appear for Improvement or additional subject<br />
examination?<br />
<span style="color: blue;"><b>Ans<span style="color: red;">.</span></b> </span> For improvement examination only one chance in the succeeding year is permitted, and for<br />
the additional subject, the candidate may appear within 6 years of passing the Main examination.<br />
<b>#18. </b> What is the procedure to apply for Improvement or Additional Examination?<br />
<b><span style="color: blue;">Ans<span style="color: red;">.</span></span> </b> The admission forms for improvement or additional examination are available in the month<br />
of August every year. The examination is held along with the main examination in the month of<br />
March/April in the following year. Outstation candidates can contact their respective regional<br />
offices for the same.<br />
<b>#19.</b> Is a consolidated or combined Marks Statement issued after improvement or additional<br />
examination?<br />
<div style="color: blue;">
<b>Ans<span style="color: red;">.</span></b></div>
<ol>
<li>After improvement a consolidated marks statement reflecting the marks of main examination and improvement examination is issued.</li>
<li>But for additional subject examination, marks statement in the concerned subject only is issued.</li>
<li>In case of compartment examination a fresh marks statement is issued if the student passes that subject.</li>
</ol>
<b>#20.</b> What is the pass criteria for Class X and XII?<br />
<b><span style="color: blue;">Ans</span><span style="color: red;">.</span></b> A candidate has to pass in all five subjects to be declared Pass. However, for class X a<br />
candidate is placed in compartment up to two unqualified subjects and if he fails in one subject<br />
in Class XII the candidate is placed in compartment.<br />
<b>#21.</b> Can one appear for improvement exam along with the compartment. Exam conducted by the<br />
Board in the month of July/August?<br />
<b><span style="color: blue;">Ans<span style="color: red;">.</span></span> </b> No, a candidate can appear for improvement exam only in the very next year of passing the<br />
main exam in March.<br />
<br />
Having more questions other than this. Ask here by leaving a comment.<br />
<u><i><span style="color: #cc0000;"><b>Avanya Singh</b> </span></i></u></div>
</div>
</div>
Anonymoushttp://www.blogger.com/profile/16164436367878764320noreply@blogger.com1tag:blogger.com,1999:blog-6903716397691032792.post-29838178263201802312012-11-14T02:44:00.001-08:002012-11-14T02:44:51.362-08:00my first post<div dir="ltr" style="text-align: left;" trbidi="on">
<br /></div>
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